Помогите решить! Безотлагательно!

1
sin10xsin2x-sin8xsin4x=0
1/2cos8x-1/2cos12x-1/2cos4x+1/2cos12x=0
1/2(cos8x-cos4x)=0
1/2*(-2sin2xsin6x)=0
sin2x=02x=n,nzx=n/2,nz
sin6x=k,kxx=k/6,kx
1)-/6n/2/2
-12n3
-1/2n3/2
n=0x=0
n=1x=/2
2)-/6k/6/2
-1k3
-1/6k3
k=0x=0
k=1x=/6
k=2x=/3
k=3x=/2
2
a)3sinx+cosx=2
2(3/2sinx+1/2cosx)=2
sin(x+/6)=2/2
x+/6=-/4+2n,nzx=-512+2n,nz
x+/6=5/4+2k,kzx=13/12+2k,kz
b)1-cos(x/2)=tg(x/4)
2sin(x/4)=sin(x/4)/cos(x/4)
2sin(x/4)cos(x/4)-sin(x/4)=0,cos(x/4)