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тот же вопрос

Х+12-2х+7/8х-7=-х+19/8х=19-х/8х-7
11-х-5-4х/5х-9=6-5х/5х-9

3х+11+9+2х/х+4=5х+20/х+4=5(х+4)/х+4=5
7х-11-х-4/2х-5=6х-15/2х-5=3(2х-5)/2х-5=3
5х-11-7+2х/х-6=7х-18/х-6
4х-10/х(х-5у)-4у-2/у(х-5у)=4ху-10у-4ху-2х/ху(х-5у)=2(-5у-х)/ху(-5у-х)=2/ху

I.a) (x+12)/(8x-7) + (2x-7)/(7-8x) = (x+12)/(8x-7) - (2x-7)/(8x-7) =

=(x+12-2x+7)/(8x-7) = (19-x)/(8x-7)

б) (11-x)/(5x-9) - (5x+4)/(9-5x) = (11-x)/(5x-9) + (5x+4)/(5x-9) =

(11-x+5x-4)/(5x-9) = (4x+7)/(5x-9)

II. a) (3x+11)/(x+4) + 9+2x)/(x+4) = (3x+11+9+2x)/(x+4) = (5x+20)/(x+4) =

   = 5(x+4)/(x+4) =5

б) (7x-11)/(2x-5) + (x+4)/(5-2x) = (7x-11)/(2x-5) - (x+4)/(2x - 5) =

=(7x-11-x-4)/(2x-5) = (6x-15)/2x-5) = = 3(2x-5)/(2x-5) = 3

в) (5x-11)/(x-6) - (7+2x)/(x-6) = (5x-11-7-2x)/(x-6) = (3x-18)/(x-6) =

   = 3(x-6)/(x-6) = 3

г)  (4x-10)/(x^2-5xy) - (4y-2)/(xy - 5y^2) = (4x-10)/x(x-5y) - (4y-2)/y(x - 5y) =

   = (4xy - 10y - 4xy + 2)/xy(x-5y) = (2x-10y)/xy(x-5y) =2(x-5y)/xy(x-5y) =

  = 2/xy