1а) [tex] fraca^2 b12c * frac4cab^2 [/tex]б) [tex]- frac2x3y *

1
а
a/3b
б
-1/9
в
(a-b)(a+b)/(a+3b)*2(a+3b)/[b(a+b)]=2(a-b)/b
г
(c+2)/[2(c-3)]*(c-3)(c+3)/[5(c+2)]=(c+2)(c+3)/10
2
а
a/(a-b)-(a-b)/(a+b)=(a+ab-a+2ab-b)/(a-b)=(3ab-b)/(a-b)
б
a/[(a-1)(a=1)]-a/(a-1)=(a-a+a)/(a-1)=a/(a-1)
в
(a+y)/[y(a-y)-20/(a-y)=(a+y-20y)/(ay-y)
г
a/[3(a+b)]*(a-b)(a+b)/a=(a-b)/3a
д
1)a+1+1/(a-1)=(a-1+1)/(a-1)=a/(a-1)
2)a/(a-1)*(a-1)/a=a-1