Помогите пожалуйста решить!

(11х-4)/5х/2                                            (х-1)/х-6  0     х-1=0     х=1  х-6=0

22х-85х                                                   х+10        х-1                               х=6

5х-22х+80                                             х+1=0                         --+----1----_--------6--+---------                                                х=-1          

5х-22х+8=0                                                                              ---  -1--1---------------                                                                                  х[1;6]

х1,2=(11 +/-121-40)/5=(11+/-81)/5      

х1=(11+9)/5=4     х2=2/5=0,4

(х-4)(х-0,4)0

---+----- 0,4 ---  -  ----4     -----+-----

х[0,4;4]

        у=х+4 + 2Х+3        Х+40     X-4          2X+30      2X-3      X-3/2

            ---------------- -4 \\\\\\\\\\\\\\\\\\\ -3/2\//////////////////////////////-

             Х[-1,5;+]