розвязати термвново!!!!!!???

1)log(2)log(3)log(4)x=0;xgt;0
log(3)log(4)x=2^0
log(4)x=3
x=4
x=64

2)log(4)log(3)log(2)x=0;xgt;0
log(3)log(2)x=4^0=1

log(2)x=3

x=2
x=8

3)log(3)log(2)log(4)x=0;xgt;0
log(2)log(4)x=3^0=1
log(4)x=2
x=4
x=16

4)log(2)log(4)log(3)x=0;xgt;0

log(4)log(3)x=2^0=1

log(3)x=4
x=3
x=81