Помогите решить Пределы

1) f(x) = 3ln(2x+1)

f'(x) = 6/(2x+1)

f'(0) = 6

2) f(x) = 5x+lnx

f'(x) = 5+1/x

f'(1) = 5 +1 = 6

3) y = xlnx

y'=2xlnx + x*1/х

y'(1) = 0 + 1 = 1

4) y = ln5x

y'= 2ln5x*1/5x*5 = 2ln5x/x

5) y = ln((x-2)/(x+2) )

y' = (x+2)/(x-2) * ((x-2)/(x+2) )'= (x+2)/(x-2) * (x+2 -x+2)/(x+2)=

=(x+2)/(x-2) * 4/(x+2) = 4/(x-4)

6) y = 3^(2x -4)

y'=3^(2x-4)*ln3*(2x -4)' = 3^(2x-4)*ln3*4x

y'(0) = 0

7) f(x) = (1/3)^(x -3x)

f'(x) = (1/3)^(x -3x) * ln(1/3)*(2x-3)

8) y = 3^x * x

y'=( 3^x)' * x + 3^x * (x)' = 3^x*ln3*x + 3^x*3x

y'(0) = 0

9)f(x) = (e^2x - e^-2x)/2

f'(x) = 2e^2x/2 +2e^-2x/2=e^2x +e^-2x

f'(0) = 1 +1 = 2

10)y = lnSinx/4

y' =1/Sinx/4 * 4Sinx/4 * 1/4