решить неравенство:))))))

3*9^x-10*3^x+3gt;=0
3^x=t
tgt;0
3t^2-10t+3gt;=0
t12=(10+-корень(100-36))/6=(10+-8)/6=3 1/3
3(t-3)(t-1/3)gt;=0
==============1/3=============3=============
++++++++++++++    ----------------------  ++++++++++
tlt;=1/3
3^xlt;=1/3
xlt;=-1
tgt;=3
3^xgt;=3
xgt;=1
xlt;=-1 xgt;=1
-------------------------
log^2 1/2 x + 2 log 1/2 x -3 gt;0
log1/2 x=t
xgt;0
t^2+2t-3gt;0
(t+3)(t-1)gt;0
===========-3============1===========
+++++++++++    ------------------- +++++++++++
tlt;-3 tgt;1
log1/2 x gt; 1
log1/2 xgt;log1/2 1/2
(1/2-1)(x-1/2)gt;0
xlt;1/2
log1/2 xlt;-3
log 1/2 x lt; log 1/2 8
(1/2-1)(x-8)lt;0
x-8gt;0
xgt;8

 x=(0 1/2) U (8 + бесконечность)