РЕШИТЕ СИММЕТРИЧЕСКУЮ СИСТЕМУ!!!(x+y)^2-4(x+y)=45(x-y)^2-2(x-y)=3

Пусть a = x + y; b = x - y.

a - 4a = 45
a - 4a - 45 = 0
a - 4a + 4 - 49 = 0
(a - 2) - 7 = 0
(a - 2 - 7)(a - 2 + 7) = 0
(a - 9)(a + 5) = 0
a = 9 или a = -5
x + y = 9 либо x + y = -5

b - 2b = 3
b - 2b - 3 = 0
b - 2b + 1 - 4 = 0
(b - 1) - 2 = 0
(b - 1 - 2)(b - 1 + 2) = 0
(b - 3)(b + 1) = 0
b = 3 либо b = -1
x - y = 3 или x - y = -1

Решаем четыре системы:
1)
x + y = 9
x - y = 3

2x = 12
x + y = 9

x = 6
y = 3

2) 
x + y = 9
x - y = -1

2x = 8
x + y = 9

x = 4
y = 5

3) 
x + y = -5
x - y = 3

2x = -2
x + y = -5

x = -1
y = -4

4)
x + y = -5
x - y = -1

2x = -6
x + y = -5

x = -3
y = -2

Ответ: (-3; -2), (-1; -4),  (4; 5), (6; 3).