1-10/x+3=50/x^2+x-6-2/x-2

1-10/(x+3)=50/(x+x-6)-2/(x-2)
x+x-6=0
по теореме Виета:
х1+х2=-1
х1*х2=-6
х1=-3
х2=2
x+x-6=(х+3)(х-2)
50/(х+3)(х-2)-2/(x-2)+10/(x+3)-1=0
(50-2(х+3)+10(х-2)-(x+x-6))/(х+3)(х-2)=0
(50-2х-6+10х-20-x-x+6)/(х+3)(х-2)=0
(-x+7х+30)/(х+3)(х-2)=0
(x-7х-30)/(х+3)(х-2)=0
х