Поясните как решать это....

2
ОДЗ xgt;0
(2+4log(4)x+11)/(log(4)x-9)-1
(4log(4)x+13)/(log(4)x-9)+10
(4log(4)x+13+log(4)x-9)/(log(4)x-9)0
log(40x=t
(t+4t+4)/(t-9)0
(t+2)/(t-3)(t+3)0
t=-2  t=3  t=-3
  +           _                    _             +
------(-3)--------[-2]----------(3)-------------
tlt;-3log(4)xlt;-3xlt;1/64
t=-2log(4)x=-2x=1/16
tgt;3log(4)xgt;3xgt;64
x(0;1/64) U (64;) U 1/16
3
[2^x*(5^x-25)-2(5^x-25)]/([(x-4)(x-1)]0
(2^x-2)(5^x-25)/(x-4)(x-1)0
x=1  x=2  x=4  
  _             +                _              +
-------(1)----------[2]----------(4)----------
x(-;1) U [2;5)
4
ОДЗ
(x-3)(x+3)gt;0
xlt;-3 U xgt;3
log(2)(x-9)=t
t-9t+200
t1+t2=9 U t1*t2=20
t1=4 U t2=5
t4log(2)(x-9)4x-916x-250(x-5)(x+5)0-5x5
t5log(2)(x-9)5x-932x-410(x-41)(x+41)0x-41 U x41
\\\\\\\\\\\\\                                                                           ///////////////
--------[-41]-----------[-5]-------[-3]--------[3]-----[5]---------[41]--------
                                 /////////////////////////////////////////
////////////////////////////////////////////////              \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\
x[-5;-3] U [3;5]
5
2^x=t
t-6(9t-37)/(t-4)(t-3)+1/(t-4)
t-6(9t-37+t-3)/(t-4)(t-3)
t-610(t-4)/(t-4)(t-3)
t-610/(t-3),t