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В1.
$\fraca ^3 a ^2 - 4 + \fraca2 - a - \frac2a + 2 - a + 4 = \\ \\ = \frac a^3 (a - 2)(a + 2) - \fracaa - 2 - \frac2a + 2 - \fraca ^3 - 4a a^2 - 4 + \frac4 a^2 - 16 a^2 - 4 = \\ \\ = \frac a^3 a^2 - 4 - \fraca ^2 + 2a a ^2 - 4 - \frac2a - 4 a^2 - 4 - \fraca ^3 - 4a a^2 - 4 + \frac4 a^2 - 16 a^2 - 4 = \\ \\ = \frac a^3 - a^2 - 2a - 2a + 4 - a^3 + 4a + 4 a^2 - 16 a^2 - 4 = \\ \\ = \frac3 a^2 - 12 a^2 - 4 = \\ \\ = \frac3(a ^2 - 4) a^2 - 4 = \\ \\ = \frac3(a - 2)(a + 2)(a - 2)(a + 2) = \\ \\ = 3$
Ответ: 3

С1.
$\frac1x(x + 1) + \frac1(x + 1)(x + 2) + \frac1(x + 2)(x + 3) - \frac3x(x + 3) - 3 = \\ \\ = \fracx ^2 + 5x + 6 + x ^2 + 3x + x ^2 + x - 3x ^2 - 9x - 6 - 3(x ^2 + x)(x ^2 + 5x + 6)x(x + 1)(x + 2)(x + 3) = \\ \\ = \frac - 3(x ^4 + 5x ^3 + 6x ^2 + x ^3 + 5x ^2 + 6x)x(x + 1)(x + 2)(x + 3) = \\ \\ = \frac - 3x ^4 - 15x ^3 - 18x ^2 - 3x ^3 - 15x ^2 - 18x x ^4 + 6x ^3 + 11x ^2 + 6x = \\ \\ = \frac - 3x ^4 - 18x ^3 - 33x ^2 - 18xx ^4 + 6x ^3 + 11x ^2 + 6x = \\ \\ = \frac - x(3x ^3 + 18x ^2 + 33x + 18) x(x ^3 + 6x ^2 + 11x + 6) = \\ \\ = \frac - (3x ^3 + 33x)(18x ^2 + 18) (x ^3 + 11x)(6x ^2 + 6) = \\ \\ = - \frac3x(x ^2 + 11) + 18(x ^2 + 1) x(x ^2 + 11) + 6(x ^2 + 1) = \\ \\ = - \frac3x + 18x + 6 = \\ \\ = - \frac3(x + 6)x + 6 = \\ \\ = - 3$
Ответ: -3

О проекте

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