Решите уравнение: (5x 1)(x +2) +3(x 4)(x +4) =2(2x +3)^2 8

( 5х - 1 )( Х + 2 ) + 3( Х - 4 )( Х + 4 ) = 2( 2х + 3 )^2 - 8
5х^2 + 10х - Х - 2 + 3( х^2 - 16 ) = 2( 4х^2 + 12х + 9 ) - 8
5х^2 + 9х - 2 + 3х^2 - 48 = 8х^2 + 24х + 18 - 8
8х^2 + 9х - 50 = 8х^2 + 24х + 10
9х - 50 = 24х + 10
24х - 9х = - 50 - 10
15х = - 60
Х = - 60 : 15 
Х = - 4 

(5х-1)*(х+2)+3(х-4)(х+4)=2(2х+3)^2-8

5x^2+10x-x-2+3(x^2-16)=2(4x^2+12x+9)-8

5x^2+10x-x-2+3x^2-48=8x^2+24x+18-8

8x^2+9x-50=8x^2+24x+10

9x-50=24x+10

9x-24x=10+50

-15x=60

x=-4