Решить систему уравнений y^2-2xy=32 и x^2+6xy+9y^2=100.Жду)

$\left \ y^2-2xy=32 \atop x^2+6xy+9y^2=100 \right. \\\\amp;10; \left \ y^2-2xy=32 \atop (x+3y)^2-10^2=0 \right. \\\\amp;10; \left \ y^2-2xy=32 \atop x^2+6xy+9y^2=100 \right. \\\\amp;10; \left \ y^2-2xy=32 \atop [x+3y+10]*[x+3y-10]=0 \right. \\\\amp;10; \left \ y^2-2xy=32 \atop x+3y+10=0 \right.\ or\ \left \ y^2-2xy=32 \atop x+3y-10=0 \right. \\\\amp;10; \left \ y^2-2y(-3y-10)-32=0 \atop x=-3y-10 \right.\ or\ \left \ y^2-2y(-3y+10)-32=0 \atop x=-3y+10 \right. \\\\$

$\left \ y^2+6y^2+20y-32=0 \atop x=-3y-10 \right.\ or\ \left \ y^2+6y^2-20y-32=0 \atop x=-3y+10 \right. \\\\amp;10; \left \ 7y^2+20y-32=0 \atop x=-3y-10 \right.\ or\ \left \ 7y^2-20y-32=0 \atop x=-3y+10 \right. \\\\amp;10;D_1=D_2=20^2-4*7*(-32)=400+896=1296=36^2\\\\amp;10; \left \ y=\frac-20\pm362*7=\frac-10\pm187 \atop x=-3y-10 \right.\ or\ \left \ y=\frac20\pm362*7=\frac10\pm187 \atop x=-3y+10 \right. \\\\$

$\left \ y=\frac-20\pm362*7=\frac-10\pm187 \atop x=-3y-10 \right.\ or\ \left \ y=\frac20\pm362*7=\frac10\pm187 \atop x=-3y+10 \right. \\\\amp;10; \left \ y=-4\ \ or\ \ y=\frac87 \atop x=-3y-10 \right.\ \ or\ \ \left \ y=4\ \ or\ \ y=-\frac87 \atop x=-3y+10 \right. \\\\amp;10;(2;\ -4)\ or\ (-\frac947;\ \frac87)\ or\ (-2;\ 4)\ or\ (\frac947;\ -\frac87)\\\\amp;10;(\pm2;\ \mp4)\ or\ (\pm\frac947;\ \mp\frac87)$

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Решить систему уравнений y^2-2xy=32 и x^2+6xy+9y^2=100.Жду)

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