Помогите по-братски.

1) x/2(x+3) -2/x=0
(x-4(x+3)/2x(x+3)=0
x-4x-12=0
D=b-4ac(a=1,b=-4,c=-12)
D=16+48=64=8
x1,x2=(-b+-корень изD)/2a
x1=(4-8)/2= -2
x2=(4+8)/2=6

2) (6(x+1)+6x)=5x(x+1)
6x+6+6x=5x+5x
12x+6-5x-5x=0
-5x+7x+6=0 *(-1)
5x-7x-6=0
D=49+120=169=13
x1=(7-13)/10= -0.6
x2=(7+13)/10= 2

3) (x-12-x)/x=0
x-x-12=0
D=1+48=49
x1=(1-7)/2= -3
x2=(1+7)/2=4

4) x(x+2)-7(x-2)-8=0
x+2x-7x+14-8=0
x-5x+6=0
D=25-24=1
x1=(5-1)/2=2
x2=(5+1)/2=3

5) 9/(x-3)= -9(3-x)
3x-9-x(3-x)=0
3x-9-3x+x=0
x-9=0
(x-3)(x+3)=0
x-3=0, x1=3, x+3=0, x2= -3

6)
2x(2x+3)-15+32x-3x(2x-3)= =0
4x+6x-15+32x-6x+9x=0
30x+15x-15=0, :15
2x+x-1=0
D=1+8=9=3
x1=(-1-3)/4= -1
x2=(-1+3)/4=0.5