Решите:1) cosx-cos5x=02) То, что на картинке

sinx = -cosx cosx

2sinx+sin2x=2 sin2x-2(1-sinx) =0 1 -cos2x-2cosx =01 -cos2x -(1 +cos2x) =0 cos2x(cos2x +1) =0

2*cosx * cos2x=0

Ответ
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Cosx-cos5x=0
2sin3x*sin2x=0
sin3x=03x=kx=k/3,kz
sin2x=02x=kx=k/2,kz

sinx+cosx=0
(sinx+cosx)(sinx-sinxcosx+cosx)=0
sinx+cosx=0/cosx
tgx+1=0tgx=-1x=-/4+k,kz
sinx-sinxcosx+cosx=0
1-1/2*sin2x=0
1/2*sin2x=1
sin2x=2gt;1 нет решения

2sinx+sin2x=2
2*(1-cos2x)/2+(1-cos4x)/2=2
2-2cos2x+1-cos4x=4
-2cos2x-2cos2x+1+3-4=0
2cos2x+2cos2x=0
2cos2x(cos2x+1)=0
cos2x=02x=/2+kx=/4+k/2,kz
cos2x=-12x=+2kx=/2+k,kz