Как найти тангенс пи/12?

when x/2 = pi/12

x = 2(pi/12) = pi/6

so when tan(x/2) = sinx /(1 + cosx)

so tan(pi/12) = sin(pi/6) / [1 + cos(pi/6)]

now substitute sin(pi/6) = 1/2 and

cos(pi/6) = 3/2

tan(pi/12) = (1/2) / (1 + 3/2) = (1/) / (2 + 3)

now rationalize the denominator by multiplying with (2 - 3) / (2 -3)

tan(pi/12) = (2 - 3) / (2 + 3)(2 - 3)

tan(pi/12) = (2 - 3) /(4 - 3) = (2 - 3)