решите уравнение (log(3)x+8) 1 =log(3)2-log(3)x-8

(log(x+8)) 1 = log2-log(x-8)   ОДЗ  х+8gt;0  x gt; - 8   x-8gt;0 x gt;8

1/2log(x+8) 1 = log2 - 1/2log (x-8)

1/2log(x+8) +1/2log (x-8) = log2 +1

1/2 *( log(x+8) +log (x-8) = log2 +log3

log(x+8) *(x-8) = 2* log2*3

log(x-8 ) = log6

х-64=36

х=100

х=10   х= -10

Ответ с учетом ОДЗ х=10