The reaction proceeds at a temperature of 500C for nbsp;3 min

given:
= 3
1 = 3 min 20 s
t1 = 500С
t2 = 300С
find:
2 -?
Solution:
=^^((t-t)/10),()/()=^(t/10)
nbsp;inversely proportionalt0 С
1) nbsp;^(t/10) nbsp;=3^((50-30)/10) nbsp;=3=9
In 9 times the rate of reaction will decrease as the temperature decreases from 500C to 300C
2) nbsp;nbsp;Time of course of the reaction at lower temperatures will increase by
9 times :200 sec 9 = 1800 sec = 30 минут nbsp;- за столько медли завершится эта реакция при снижении температуры с 500С до 300С.
Answer: nbsp;nbsp;at a temperature of 300 C for 30min the reaction stops.