Помогите отыскать x,y,z.Пожалуйста

P(ABC) = x+y+z = 36.

По подобию: x/12 = y/18 = z/24 = t,

x = 12t,

y = 18t,

z = 24t,

P(ABC) = x+y+z = 12t + 18t + 24t = 30t + 24t = 54t = 36,

отсюда t = 36/54 = (9*4)/(9*6) = 4/6 = 2/3.

Тогда,

x = 12*(2/3) = 4*2 = 8,

y = 18*(2/3) = 6*2 = 12,

z = 24*(2/3) = 8*2 = 16.