Помогите решить уравнение. Срочно!!2sin(/4-x/3)+2=0

2sin(/4-x/3)+2=0

2sin(/4-x/3) = - 2

sin(/4-x/3) = -2/2

/4-x/3 = (-1)^n arcSin(-2/2) +n, n Z

/4-x/3 = (-1)^n */4 +n, n Z

-х/3 = (-1)^n /4 + n -/4 , n Z

x = (-1)^(n+1) 3/4 - 3n -3/4, nZ

2sin(/4-x/3)+2=0

2sin(/4-x/3)=-2 :2

сos(x/3+/4)=-2/2

x/3+/4=n-+arccos(-2/2)

x/3+/4=n+3/4

x/3+/4=n-/4

x/3=n+/2

x/3=n-/2 : 1/3

Ответ:

x1=3n+3/2

x2=3