Выполнить арифметические операции:- в двоичной системе счисления : 1010 * 10111,

1010 * 10111 = 11100110

1) 1010 = 1 * 2 + 0 * 2 + 1 * 2 + 0 * 2 = 8 + 2 = 10

2) 10111 = 1 * 2 + 0 * 2 + 1 * 2 + 1 * 2 + 1 * 2 = 16 + 4 + 2 + 1 = 23

3) 10 * 23 = 230 4) 230 = 11100110 230 / 2 = 115 (ост. 0) / 2 = 57 (ост. 1) / 2 = 28 (ост. 1) / 2 = 14 (ост. 0) / 2 = 7 (ост. 0) / 2 = 3 (ост. 1) / 2 = 1 (ост. 1)

101010 - 1111 = 11011

1) 101010 = 1 * 2 + 0 * 2 + 1 * 2 + 0 * 2 + 1 * 2 + 0 * 2 = 32 + 8 + 2 = 2423

2) 1111 = 1 * 2 + 1 * 2 + 1 * 2 + 1 * 2 = 8 + 4 + 2 + 1 = 15

3) 42 - 15 = 27 4) 27 = 11011  27 / 2 = 13 (ост. 1) / 2 = 6 (ост. 1) / 2 = 3 (ост. 0) / 2 = 1 (ост. 1)

4567 + 654 = 5443

1) 4567 = 4 * 8 + 5 * 8 + 6 * 8 + 7 * 8 = 2048 + 320 + 48 + 7 = 2423

2) 654 = 6 * 8 + 5 * 8 + 4 * 8 = 384 + 40 + 4 = 428

3) 2423 + 428 = 2851 4) 2851 = 5443 2851 / 8 = 356 (ост. 3) / 8 = 44 (ост. 4) / 8 = 5 (ост. 4) = 5443

365 * 777 = 364413

1) 365 = 3 * 8 + 6 * 8 + 5 * 8 = 192 + 48 + 5 = 245

2) 777 = 7 * 8 + 7 * 8 + 7 * 8 = 448 + 56 + 7 = 511

3) 245 * 511 = 125 195 4) 125195 = 364413  125 195 / 8 = 15649 (ост. 3) / 8 = 1956 (ост.1) / 8 = 244 (ост. 4) / 8 = 30 (ост. 4) / 8 = 3 (ост. 6)