Решите уравнения :121a - 25 = 0(1 - 2b)(1+2b)+4b(b-2)=49(x-2)+(x+2)=2(x-3)(x+3x+9)

1) 121a - 25 = 0

1) 121 a -25 = 0

1) 121a  - 25 =0
(11a-5)(11a+5)=0
11a-5=0
a=5/11
11a+5=0
a=-5/11
2) (1-2b)(1+2b)+4b(b-2)=49
(1-4b )+4b -8b=49
1-8b=49
48=-8b
b=-6
3)(x-2)+(x+2)=2(x-3)(x+3x+9)
(x-6x+12x-8)+(x+6x+12x+8)=(2x-6)(x+3x+9)=2x+6x+18x-6x-18x-54=2x-54
2x+24x=2x-54
x+12x=x-27
x+12x-x+27=0
12x=-27
x=-27/12=-2.25