[tex] frac7cc + 2 - fracc - 83c + 6 times

Ответ:

Пошаговое разъясненье:

1) ((c-8)/(3c+6))*(84/(c-8c)=(c-8)*84/(3*(c+2)*c*(c-8))=84/(3c*(c+2)).

2) (7c/(c+2))-84/(3c*(c+2)=(7c*3c-84)/(3c*(c+2)=(21c-84)/(3c*(c+2)=

=21*(c-4)/(3c*(c+2))=7*(c+2)*(c-2)/(c*(c+2))=7*(c-2)/c.

Ответ:

7c/(c+2) - (c-8)*84 / 3(c+2)*c(c-8)=

7c/(c+2) - 28/c(c+2)=

(7c^2-28) / c(c+2)=7(c^2-4) / c(c+2)=7(c-2)(c+2) / c(c+2)=7(c-2)/c.

Пошаговое изъясненье: