Решите уравнение x^2-35=2x

x^2 35 = 2x;
x^2 2x 35 = 0;
D = b^2 - 4*a*c ;
a = 1; b = -2; c = -35 ;
D = (-2)^2 - 4*1*(-35) = 4 + 140 = 144 ;
x1 = (-b + D) / 2*а = (2 + 144) / 2*1 = (2 + 12) / 2 = 14 / 2 = 7.
х2 = (-b - D) / 2*а = (2 - 144) / 2*1 = (2 - 12) / 2 = -10 / 2 = -5.
Ответ: х1 = 7; х2 = -5.