3 + 2 log x+1 3 = 2 log 3 x+1

3 + 2 log(x + 1) 3 = 2 log(3) (x + 1);

3log(3) 3 + 2/log(3) x + 1 = 2log(3) x + 1;

(3log(3) 3 * log(3) (x + 1) + 2log(3) 3)/(log(3) (x + 1)) = 2log(3) (x + 1);

2log(3)^2 (x + 1) = 3log(3) (x + 1) + 2;

log(3) (x + 1) = t;

2t^2 - 3t - 2 = 0;

D = 9 + 16 = 25;

t = (3 +- 5)/4;

t = 2, t = -1/2;

log(3) (x + 1) = 2;

3^2 = x + 1;

9 = x + 1;

x = 8;

log(3) (x + 1) = -1/2;

3^-1/2 = x + 1;

1/sqrt3 = x + 1;

x = sqrt3/3 - 1 = (sqrt3 - 3)/3.