Решите уравнение :(х+1)(х+2)=(х-3)(х+4) (3х-1)(2х+7)-(х+1)(6х-5)=16 24-(3у+1)(4у-5)=(11-6у)(2у-1)+6 (6у+2)(5-у)=47-(2у-3)(3у-1)

1) (x + 1) * (x + 2) = (x - 3) * (x + 4);

x^2 + 2x + x + 2 = x^2 + 4x - 3x - 12;

x^2 - x^2 + 2x + x - 4x + 3x = -12 - 2;

3x - x = -14;

2x = -14;

x = -14 : 2;

x = -7.

2) (3x - 1) * (2x + 7) - (x + 1) * (6x - 5) = 16;

6x^2 + 21x - 2x - 7 - 6x^2 + 5x - 6x + 5 = 16;

19x - x = 16 + 7 - 5;

18x = 18;

x = 18 : 18;

x = 1.

3) 24 - (3y + 1) * (4y - 5) = (11 - 6y) * (2y - 1) + 6;

24 - 12y^2 + 15y - 4y + 5 = 22y - 11 - 12y^2 + 6y + 6;

-12y^2 + 12y^2 + 11y - 22y - 6y = -5 - 24 - 5;

-17y = -34;

y = -34 : (-17);

y = 2.

4) (6y + 2) * (5 - y) = 47 - (2y - 3) * (3y - 1);

30y - 6y^2 + 10 - 2y = 47 - 6y^2 + 2y + 9y - 3;

30y - 6y^2 + 6y^2 - 2y - 2y - 9y = 47 - 3 - 10;

17y = 34;

y = 34 : 17;

y = 2.