Решите уравнение:1)(х+4)^2=3х+402)(2х-3)^2=11x-193)(x+1)^2=7918-2x4)(x+2)^2=3131-2x

1) (х + 4)² = 3х + 40;

х² + 8х + 16 - 3х - 40 = 0;

х * (х + 8) - 3 * (х + 8) = 0;

(х + 8) * (х - 3) = 0;

х₁ = - 8, х₂ = 3.

2) (2х - 3)² = 11х - 19;

4х² - 12х + 9 - 11х + 19 = 0;

х * (4х - 7) - 4 * (4х - 7) = 0;

(4х - 7) * (х - 4) = 0;

х₁ = 7/4, х₂ = 4.

3) (х + 1)² = 7918 - 2х;

х² + 2х + 1 - 7918 + 2х = 0;

х * (х - 87) + 91 * (х - 87) = 0;

(х - 87) * (х + 91) = 0;

х₁ = 87, х₂ = - 91.

4) (х + 2)² = 3131 - 2х;

х² + 4х + 4 - 3131 + 2х = 0;

х * (х + 59) - 53 * (х + 59) = 0;

х₁ = - 59, х₂ = 53.