6х в квадрате+5mx+m в квадрате=0

   Решим уравнение относительно каждой переменной:

   1. переменная - x:

• 6х^2 + 5mx + m^2 = 0;

• a = 6;
• b = 5m;
• c = m^2;

• D = b^2 - 4ac;
• D = (5m)^2 - 4 * 6 * m^2 = 25m^2 - 24m^2 = m^2;

• x = (-b D)/2a;
• x = (-5m (m^2))/(2 * 6) = (-5m m)/12;

• x1 = (-5m - m)/12 = -6m/12 = -m/2;
• x2 = (-5m + m)/12 = -4m/12 = -m/3.

   2. переменная - m:

• m^2 + 5xm + 6х^2 = 0;

• a = 1;
• b = 5x;
• c = 6x^2;

• D = b^2 - 4ac;
• D = (5x)^2 - 4 * 1 * 6x^2 = 25x^2 - 24x^2 = x^2;

• m = (-b D)/2a;
• m = (-5x (x^2))/2 = (-5x x)/2;

• m1 = (-5x - x)/2 = -6x/2 = -3x;
• m2 = (-5x + x)/2 = -4x/2 = -2x.