Решить уравнение а)х(1,2х-3)=0 б)(2х-3)^2-2х(4+2х)=11

а) Найдем корень уравнения.

х * (1,2 * х - 3) = 0; 

x = 0;

1.2 * x - 3 = 0;

x = 0;

1.2 * x = 3;

x = 0;

x = 3/1.2;

x = 0;

x = 30/12;

x = 0;

x = 10/4;

x = 0;

 x = 5/2;

x = 0;

x = 2.5.

б)(2 * х - 3) - 2 * х * (4 + 2 * х) = 11; 

(2 * x) - 2 * 2 * x * 3 + 3 - 2 * 4 * x - 2 * x * 2 * x = 11; 

4 * x - 12 * x + 9 - 8 * x - 4 * x = 11; 

-12 * x + 9 - 8 * x = 11; 

-20 * x + 9 = 11; 

-20 * x = 11 - 9; 

-20 * x = 2; 

x = -2/20; 

x = -1/10; 

x = -0.1.