Второе задание ,пожалуйста (50 баллов)

1)(xy)^2= (12*-0.5)^2=-6^2=36;=(-14*-1)^2=14^2=196

2)(x/y)^3=(-6/1.5)^3=(-4)^3=-64;=(0/-23)^3=0^3=0

3)(x+y)^4=(0.7+0.3)^4=1^4=1;=(-11+6)^4=(-5)^4=625

4)(y-x)^3=(-14+10)^3=(-4)^3=-64;=(0.9-1.1)^3=(-0.2)^3=-0.008

(12*(-0,5)) = (-6) = 36

(-14*(-1)) = 14 = 196

(-6/1,5) = (-4) = -64

(0/(-23)) = 0 = 0

(0,7+0,3) = 1 = 1

(-11+6) = (-5) = 625

(-10-(-14)) = (-10+14) = 4 = 64

(1,1-0,9) = 0,2 = 0,008