Отыскать интегралы .1) (4-3 cos x) dx ; 2)

1.(4-3cosx)dx=4x-3sinx+C
2.cos4xdx=1/4cosudu=sinu/4+C=1/4*sin(4x)+C
u=4x
du=4dx
3.cos(x/6)dx=6cosudu=6sinu+C=6sin(x/6)+C
u=x/6
du=1/6*dx
4.cos(2-3x)dx=-1/3cosudu=-sinu/3+C=-1/3*sin(2-3x)+C
u=2-3x
du=-3dx
5.xcosxdx=1/2xcosx(cos2x+1)dx=1/2(xcosx+xcosxcos2x)dx=1/2xcosxcos2xdx+1/2xcosxdx=1/4x(cosx+cos3x)dx+1/2xcosxdx=1/4(xcosx+xcos3x)dx+1/2xcosxdx=1/4xcos3xdx+3/4xcosxdx=1/12*x*sin3x-1/6xsin3xdx+3/4xcosxdx=1/18*x*cos3x+1/12*x*sin3x-1/18cos3xdx+3/4xcosxdx=1/18*x*cos3x+1/12*x*sin3x-1/54cosudu+3/4xcosxdx=1/18*x*cos3x+1/12*x*sin3x-sinu/54+3/4xcosxdx=1/18*x*cos3x+1/12*x*sin3x-sinu/54+3/4*xsinx-3/2xsinxdx=1/18*x*cos3x+1/12*x*sin3x-sinu/54+3/4*xsinx+3/2xcosx-3/2cosxdx=1/18*x*cos3x+1/12*x*sin3x-sinu/54+3/4*xsinx+3/2*xcosx-3sinx/2+C=3/4*xsinx+1/12*x*sin3x-3sinx/2-1/54*sin3x+3/2*x*cosx+1/18*x*cos3x+C
u=3x
du=3dx