Помогите!!! Необходимо решить с:1) 2 (3+y) + 3 (2y+4) = 22)

Помогите!!! Нужно решить с:
1) 2 (3+y) + 3 (2y+4) = 2
2) 3 (3u + 1) - 4 (u-4) = 29
3) 7 (2x + 3) = 91 - 4 (3x - 2)
4) 5 (2z - 3) = 6 (3z + 2) - 35
5) 2 (2v - 4) = 4 (3 - v) - 44
6) 6 (2t - 5) + 2 (3t - 7) = -26
7) 5 (3z - 2) = -16-3 (2z + 5)
8) 8 (2 - x) = 3 (4x + 3) + 87
9) 4 (6y - 5) = 5 (2y - 3) + 51
10) 5 (7 - 2s) - 4 (3 - 5s) =53
11) 3 (2z - 1) = 55 - 4(z + 2)
12) 5 (2 - v) - 2 (2v - 1) - 26 = 0
13) 3 (x - 4) + 7 (2x - 3) = -84
14) 2 (2u + 3) - 4 (3 - 2u) = -6