сделайте 2 варианта пожалуйста))))

Опыт 1
А) I вар\
Al[3+] + 3OH[-] = Al(OH)3
Al[3+] + 3NO3[-] + 3K[+] + 3OH[-] = Al(OH)3 + 3K[+] + 3NO3[-]
Al(NO3)3 + 3KOH = Al(OH)3 + 3KNO3
II вар\
Cu[2+] + 2OH[-]  = Cu(OH)2
Cu[2+] + SO4[2-] + 2K[+] + 2OH[-]  = Cu(OH)2 + 2K[+] + SO4[2-]
CuSO4 + 2KOH = Cu(OH)2 + K2SO4
Б) I вар\
NH4[+] +  OH[-] = NH3 + H2O
 NH4[+] + Cl[-] + K[+] + OH[-] = NH3 + H2O + K[+] + Cl[-]
NH4Cl + KOH = NH3 + H2O + KCl
II вар\
CO3[2-] + 2H[+] = CO2 + H2O
2Na[+] + CO3[2-] + 2H[+] + 2Cl[-] = 2Na[+] + 2Cl[-] + CO2 + H2O
Na2CO3 + 2HCl = 2NaCl + CO2 + H2O
В) H[+] + OH[-] = H2O
K[+] + OH[-] = K[+] + Cl[-] + H2O
KOH + HCl = KCl + H2O  
Опыт2
BaCl2 + H2SO4 = BaSO4 + 2HCl
Ba[2+] + 2Cl[-] + 2H[+] + SO4[2-] = BaSO4 + 2H[+] + 2Cl[-]
Ba[2+] + SO4[2-] = BaSO4  
FeCl3 + 3KOH = Fe(OH)3 + 3KCl
Fe[3+] + 3Cl[-] + 3K[+] + 3OH[-] = Fe(OH)3 + 3K[+] + 3Cl[-]
Fe[3+] + 3OH[-] = Fe(OH)3
  K2S + 2HCl = 2KCl + H2S
2K[+] + S[2-] + 2H[+] + 2Cl[-] = 2K[+] + 2Cl[-] + H2S
2H[+] + S[2-] = H2S      
3 задание:
I вариант:
BaCl2 + Na2CO3 = BaCO3 + 2NaCl
Ba[2+] + 2Cl[-] + 2Na[+] + CO3[2-]= BaCO3 + 2Na[+] + 2Cl[-]
Ba[2+] + CO3[2-] = BaCO3
CaCl2 + Na2SO4 = CaSO4 + 2NaCl
Ca[2+] + 2Cl[-] + 2Naa[+] + SO4[2-] = CaSO4 + 2Na[+] + 2Cl[-]
Ca[2+] + SO4[2-] = CaSO4
Al(NO3)3 + 3NH4Cl = (реакция не идет)
II вариант:
CaCl2 + Na2CO3 = CaCO3 + 2NaCl
Ca[2+] + 2Cl[-] + 2Na[+] + CO3[2-]= CaCO3 + 2Na[+] + 2Cl[-]
Ca[2+] + CO3[2-] = CaCO3  
CaCl2 + 2NaOH = 2NaCl + Ca(OH)2
Ca[2+] + 2Cl[-] + 2Na[+] + 2OH[-] = 2Na[+] + 2Cl[-] + Ca(OH)2
Ca[2+] + 2OH[-] = Ca(OH)2  
2FeCl3 + 3CuSO4 = (реакция не идет)