Решите, пожалуйста 2 задачи :D ( Подробно )1-Какой объем водорода выделится

дано

m(Mg) = 6 g

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V(H2)-?

Mg+2CH3COOH---gt;(CH3COO)2Mg+H2

M(Mg) = 24 g/mol

n(Mg) = m/M = 6/ 24 = 0.25 mol

n(Mg) = n(H2) = 0.25 mol

V(H2) = n*Vm = 0.25 * 22.4 = 5.6 L

ответ 5.6 л

дано

m(ppa CH3COOH) = 150 g

W(CH3COOH)  = 10 %

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m(NaOH)-?

m(CH3COOH) = 150 * 10% / 100% = 15 g

CH3COOH+NaOH---gt;CH3COONa+H2O

M(CH3COOH) = 60 g/mol

n(CH3COOH) = m/M = 15 / 60 = 0.25 mol

n(CH3COOH) = n(NaOH) = 0.25 mol

M(NaOH) = 40 g/mol

m(NaOH) = n*M = 0.25 * 40  = 10 g

ответ 10 г