4, 4*, 5, 5*Помогите пж

4

CH3COOH +C3H7OH--gt;

--gt;CH3COOC3H7

n(CH3COOH) =12/60=0.2моль

n(C3H7OH)=15/60=0.25моль

n(CH3COOC3H7)=0.2моль(по уравнению реакции)

m(CH3COOC3H7)=Mr*n=102*0.2=20.4г

4*

C3H7Cl+NaOH--gt;C3H7OH+NaCl

m(NaOH)=m(р-ра)*w/100%=20%*25/100%=5г

n(NaOH)=5/40=0.125моль

n(C3H7Cl)=11.78/78.5=0.15

n(C3H7OH)=0.125моль

m(C3H7OH)=0.125*60=7.5г

5

1) C2H5OH--gt;C2H4+H2O

2)C2H4+H2O--gt;(H2SO4,t)C2H5OH

3)C2H5OH+HCl--gt;C2H5Cl+H2O

4)C2H5Cl+KOH--gt;(H2O)C2H5OH+KCl

5)2C2H5Cl+2Na--gt;2C2H5Na+H2

5*

1)CH3COONa+NaOH(тв)--gt;СН4+Na2CO3

2)2CH4--gt;(1500C)C2H2+3H2

3)C2H2+H2--gt;(Ni,t)C2H4

4)C2H4+H2O--gt;(H2SO4)C2H5OH

5)C2H5OH+CH3COOH--gt;CH3COOC2H5