Помогите пожалуйста В 300 г 6%-ного раствора уксусной кислоты растворили 6

Ответ:

дано

m(ppa CH3COOH) = 300 g

W(CH3COOH) = 6 %

+m2(CH3COOH) = 6g

w(Na2CO3) = 20%

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W1(CH3COOH)-?

m ppa (Na2CO3)-?

m(CH3COOH) = 300 * 6% / 100% = 18 g

m1(ppa CH3COOH) =m(ppa CH3COOH)+m2(CH3COOH) =  300 +6 = 306 g

m1(CH3COOH) = m(CH3COOH) + m2(CH3COOH) = 18 + 6 = 24 g

W1(CH3COOH) = m1(CH3COOH) / m1(ppa CH3COOH) * 100%

W1(CH3COOH) = 24 / 306 * 100% = 7.8 %

CH3COOH+Na2CO3--gt;CH3COONa+H2O+CO2

M(CH3COOH) = 60 g/mol

n(CH3COOH) = m1(ppa CH3COOH) / M(CH3COOH) = 306 / 60 = 5.1 mol

n(CH3COOH) = n(Na2CO3) = 5.1 mol

M(Na2CO3) = 106 g/mol

m(Na2CO3) = n*M = 5.1 * 106 = 540.6 g

m(ppa Na2CO3) = m(Na2CO3) * 100% / w(Na2CO3) = 540.6 * 100% / 20%

m(ppa Na2CO3) = 2703 g

ответ 7.8% , 2703 г

Объяснение: