Какая разица появляется при содействии 80г 60 раствора уксусной кислоты с

Ответ:

дано

m(ppa CH3COOH) = 80 g

W(CH3COOH) = 60%

(CH3COOCH3) = 90%

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m(ppa CH3COOCH3)-?

m(CH3COOH) = 80 * 60% / 100% = 48 g

CH3COOH+CH3OH--gt;CH3COOCH3+H2O

M(CH3COOH) = 60 g/mol

n(CH3COOH) = m/M = 48 / 60  = 0.8 mol

n(CH3COOH) = n(CH3COOCH3) = 0.8 mol

M(CH3COOCH3)  = 74 g/mol

m(CH3COOCH3) = n*M = 0.8 * 74 = 59.2 g

m(ppa CH3COOCH3) = 59.2 * 100% / 90% = 65.78g

ответ 65.78г

Изъясненье:

https://images.app.goo.gl/mZK48G7mmru5cSnn7