12-е задание, кто поможет?

Дано

HxSyOz

w(H) = 2.44% = 0.0244

w(S) = 39.02% = 0.3902

Решение

w(O) = 1 - w(H) - w(S) = 1 - 0.0244 - 0.3902 = 0.5854

Пусть m = 100 г, тогда

m(H) = mw(H) = 100 * 0.0244 = 2.44 г

m(S) = mw(S) = 100 * 39.02 г

m(O) = mw(O) = 100 * 0.5854 = 58.54 г

n(H) = m(H) / M(H) = 2.44 / 1 = 2.44

n(S) = m(S) / M(S) = 39.02 / 32 = 1.22

n(O) = m(O) / M(O) = 58.54 / 16 = 3.66

n(H) : n(S) : n(O) = 2.44 : 1.22 : 3.66

n(H) : n(S) : n(O) = 2 : 1 : 3

Ответ: H2SO3