Ребята, помогите, математика

(x-3x-3)/(x+2)1
1)xlt;0
(x+3x-3)/(-x+2)1
(x+3x-3)/(-x+2) -10
(x+3x-3+x-2)/(2-x)0
(x+4x-5)/(2-x)0
x+4x-5=0
x1+x2=-4 U x1*x2=-5x1=-5 U x2=1
2-x=0x=2
                    \\\\\\\\\\\\\\\\\\\\\\\                     \\\\\\\\\\\\\\\\\\\\\\\\
           +                     _                  +                   _
----------------[-5]---------(0)------[1]--------------(2)--------------------
\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\
x[-5;0)
2)x0
(x-3x-3)/(x+2)1
(x-3x-3)/(x+2) -10
(x-3x-3-x-2)/(x+2)1
(x-4x-5)/(x+2)0
x-4x-5=0
x1+x2=4 U x1*x2=-5x1=-1 U x2=5
x+2=0x=-2
\\\\\\\\\\\\\\\\\\\\\\\                      \\\\\\\\\\\\\\\\\\\\\\\\\\\\
             _                    +                 _                     +
------------------(-2)--------------[-1]----------[0]----[5]----------------
                                                             \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\
x[0;5]
Общий x[-5;5]
наим -5,наиб 5,творенье -5*5=-25
Ответ -25