Помогите пожалуйста !))) Решите уравнение log(4+x)+log(1+2x)=2log3 log(1+x)+log(2+x)=1 log(x-2)+log(x+1)=2

1) log(4 + x) + log(1 + 2 * x) = 2 * log3;
log(4 + x) + log(1 + 2 * x) = log9;
log((4 + x)*(1 + 2 * x)) = log9;
(4 + x) * (1 + 2 * x) = 9;
4 + 8 * x + x + 2 * x^2 = 9;
2 * x ^ 2 + 9 * x - 5 =0;
x = -5;
x = 0.5;

2) log(1+x)+log(2+x)=1;
log(1+x)+log(2+x)=log 2;
log((1+x)*(2+x))=log 2;
(1 + x) * (2 + x) = 2;
2 + x + 2 * x + x^ 2 - 2 = 0;
x^ 2 + 3 * x = 0;
x * (x + 3) = 0;
x = 0;
x = - 3;

3) log(x-2)+log(x+1)=2;
log(x-2)+log(x+1)=log 4;
(x - 2) * (x + 1) = 4;
x^2 + x - 2 * x - 2 - 4=0;
x^ 2 - x - 6 =0 ;
x = - 2;
x = 3.