1) log15 + log18 - log10= ....... ? 2) 2log6 -

1) log_3^2(3 * 5) + log_3^2(3^2 * 2) log_3^2(2 * 5) = 1/2(log₃(3 * 5) + log₃(3^2 * 2) log₃(2 * 5)) = 1/2(log₃3 + log₃5 + log₃3² + log₃2 log₃2 log₃5) = 1/2(1 + 2) = 3/2 = 1,5.

Ответ: 1,5.

2) 2log_{3^(- 1)} 6 1/2log_{3^(- 1)} 400 + 3log_{3^(- 1)} 45 = - 2log₃6 + 1/2log₃400 3log₃45 = - log₃6² + log₃400^1/2 log₃(45)³ = - log₃36 + log₃20 - log₃45 = log₃ (20/(36 * 45)) = log₃(1/81) = log₃81^{- 1} = log₃ 3^{- 4} = - 4 log₃3 = - 4.

Ответ: - 4.