Отыскать корень уравнения: 1/3y+2=1; 1/5x+11=1-3/5x; 8-1/4z=1; 3-5/7t=1-3/7t; 1/8u-2=5/8u+1; 2/5z-7=3

   1. Умножим обе доли на 3y:

• 1/3y + 2 = 1;
• 1 + 2 * 3y = 3y;
• 6y - 3y = -1;
• 3y = -1;
• y = -1/3.

   2.

• 1/5x + 11 = 1 - 3/5x;
• 1/5x + 3/5x = 1 - 11;
• 4/5x = -10;
• 4 = -10 * 5x;
• 4 = -50x;
• x = -4/50 = -2/25.

   3.

• 8 - 1/4z = 1;
• 8 - 1 = 1/4z;
• 7 = 1/4z;
• 7 * 4z = 1;
• 28z = 1;
• z = 1/28.

   4.

• 3 - 5/7t = 1 - 3/7t;
• 3 - 1 = 5/7t - 3/7t;
• 2 = 2/7t;
• 1 = 1/7t;
• 7t = 1;
• t = 1/7.

   5.

• 1/8u - 2 = 5/8u + 1;
• -2 - 1 = 5/8u - 1/8u;
• -3 = 4/8u;
• -3 = 1/2u;
• -3 * 2u = 1;
• -6u = 1;
• u = -1/6.

   6.

• 2/5z - 7 = 3;
• 2/5z = 3 + 7;
• 2/5z = 10;
• 2 = 10 * 5z;
• 2 = 50z;
• z = 2/50 = 1/25.