Найдите расстояние меж данными точками.1)A(2;9), B(8;1)2)K(-2;4), L(2;1)3)M(4;13),

AB = ((8-2) + (9-1)) = (36 + 64) = 100 = 10

KL = ((2+2) + (4-1)) = (16+9) = 25 = 5

MN = ((13-4) + (13-10)) = (81 + 9) = 90 = 310

PR = ((2+5) + (-1)) = (49 + 1) = 50 = 52

1) AB^2 = (8 - 2)^2 + (1 - 9)^2 = 6^2 + (-8)^2 = 36 + 64 = 100
AB = 10

2) KL^2 = (2-(-2))^2 + (1-4)^2 = 4^2 + (-3)^2 = 16 + 9= 25
KL = 5

3) MN^2 = (13-4)^2 + (10-13)^2 = 9^2 + (-3)^2 = 81 + 9 = 90
MN = 3sqrt(10)

4) PR^2 = (2-(-5))^2 + (-1-0)^2 = 7^2 + (-1)^2 = 49 + 1 = 50
PR = 5sqrt(2)