Вычислите: а)две девятых от т3 целых 3 4ых б)0.6 от 6

a) (2/9) * (3 ³/₄) = (2/9) * ((3 * 4 + 3)/4) = (2/9) * (15/4) = (2 * 15)/(9 * 4) = (2 * 3 * 5)/(3 * 3 * 2 * 2) = 5/(2 * 3) = 5/6;

б) 0,6 * 6 ²/₃ = (6/10) * ((6 * 3 + 2)/3) = (6/10) * (20/3) = (6 * 20)/(10 * 3) = (2 * 3 * 2 * 10)/(10 * 3) = 2 * 2 = 4;

в) (3/5) * x = 2,4.

Тогда x = 2,4 : (3/5) = 24/10 * 5/3 = (24 * 5)/(10 * 3) = (2 * 3 * 4 * 5)/(2 * 5 * 3) = 4.

x = 4;

г) 1,5 : 6 = 15/10 : 6 = 15/60 = 1/4;

д) 30% от y = 4 ¹/₅.

Тогда y = 4 ¹/₅ : 30% = 21/5 : 0,3 = 21/5 * 10/3 = 2 * 7 = 14.

y = 14.